PPSC Lecturer of Physics Online Test 44 Solved MCQs

Online Free Taleem is free online MCQ’s test related to Lecturer Physics. All the individuals who are going to appear in Lecturer Physics written test can attempt these tests in order to prepare for it in best possible way. Our tests of Lecturer of Physics include all the important questions and Past Paper of  Lecturer Physics, that have extremely high amount of chances for been included in the actual exam which make our test undoubtedly the best source of preparation.

Note:-

There will be 25 multiple choice question in the test.
Answer of the questions will change randomly each time you start this test.
Practice this test at least 5 times if you want to secure High Marks.
At the End of the Test you can see your Test score and Rating.
If you found any incorrect answer in Quiz. Simply click on the quiz title and comment below on that MCQ. So that I can update the incorrect answer on time.

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Test Instructions:-
Test Name Lecturer Physics 
Subject Physics Test 44
Test Type MCQs
Total Questions 25
Total Time 20 Minutes
Total Marks 100
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You have 20 minutes to pass to the quiz.


PPSC LECTURER OF PHYSICS TEST NO. 44

1 / 25

A racing car traveling with constant acceleration increases its speed from 10m/s to 50m/s over a distance of 60 m. How long does this take?

2 / 25

At time t = 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by −0.50t, in m/s2 for t in seconds. At the end of 4.0 s it has traveled:

3 / 25

How far does a car travel in 6 s if its initial velocity is 2 m/s and its acceleration is 2 m/s2 in the forward direction?

4 / 25

At a stop light, a truck traveling at 15 m/s passes a car as it starts from rest. The truck travels at constant velocity and the car accelerates at 3 m/s2. How much time does the car take to catch up to the truck?

5 / 25

A baseball is thrown vertically into the air. The acceleration of the ball at its highest point is:

6 / 25

A car starts from rest and goes down a slope with a constant acceleration of 5 m/s2. After 5 s the car reaches the bottom of the hill. Its speed at the bottom of the hill, in meters per second, is:

7 / 25

An object is thrown straight up from ground level with a speed of 50 m/s. If g = 10 m/s2 its distance above ground level 1.0 s later is:

8 / 25

Over a short interval near time t = 0 the coordinate of an automobile in meters is given by x(t) = 27t − 4.0t3, where t is in seconds. At the end of 1.0 s the acceleration of the auto is:

9 / 25

A ball is in free fall. Its acceleration is:

10 / 25

A particle moves on the x axis. When its acceleration is positive and increasing:

11 / 25

An object with an initial velocity of 12 m/s west experiences a constant acceleration of 4 m/s2 west for 3 seconds. During this time the object travels a distance of:

12 / 25

At time t = 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by −0.50t, in m/s2 for t in seconds. By the time it stops it has traveled:

13 / 25

A freely falling body has a constant acceleration of 9.8 m/s2. This means that:

14 / 25

At time t = 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by −0.50t, in m/s2 for t in seconds. It stops at t =

15 / 25

A feather, initially at rest, is released in a vacuum 12 m above the surface of the earth. Which of the following statements is correct?

16 / 25

An object is shot vertically upward. While it is rising:

17 / 25

Which one of the following statements is correct for an object released from rest?

18 / 25

Throughout a time interval, while the speed of a particle increases as it moves along the x axis, its velocity and acceleration might be:

19 / 25

An object is thrown vertically upward at 35 m/s. Taking g = 10 m/s2, the velocity of the object 5 s later is:

20 / 25

Of the following situations, which one is impossible?

21 / 25

A car, initially at rest, travels 20 m in 4 s along a straight line with constant acceleration. The acceleration of the car is:

22 / 25

A car moving with an initial velocity of 25 m/s north has a constant acceleration of 3 m/s2 south. After 6 seconds its velocity will be:

23 / 25

A particle moves along the x axis according to the equation x = 6t2, where x is in meters and t is in seconds. Therefore:

24 / 25

An object is thrown straight up from ground level with a speed of 50 m/s. If g = 10 m/s2 its distance above ground level 6.0 s later is:

25 / 25

At a location where g = 9.80 m/s2, an object is thrown vertically down with an initial speed of 1.00 m/s. After 5.00 s the object will have traveled:

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