PPSC FPSC Lecturer Chemistry Solved MCQs Test No. 61

Online Free Taleem is free online MCQ’s test related to Lecturer Chemistry. All the individuals who are going to appear in PPSC, FPSC, KKPSC, SPSC, BPSC, AJ&KPSC, NTS, Lecturer Chemistry written test can attempt these tests in order to prepare for it in best possible way. Our tests of Lecturer of Chemistry include all the important questions and Past Paper of  Lecturer Chemistry, that have extremely high amount of chances for been included in the actual exam which make our test undoubtedly the best source of preparation.

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There will be 25 multiple choice question in the test.
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Test Instructions:-
Test Name Lecturer Chemistry
Subject Chemistry Test 61
Test Type MCQs
Total Questions 25
Total Time 20 Minutes
Total Marks 100
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You have 20 minutes to pass to the quiz.


Lecturer Chemistry Online Test No. 61

1 / 25

The number of moles of KMnO4 that will be needed to react with one mole of sulphite ion in acidic solution is:

2 / 25

Percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (at. wt. = 78.4) then minimum molecular weight of peroxidase anhydrous enzymes is:

A). 1.568 × 103

B). 1.568 × 104

C).  25.68

D). 4.316 × 104

3 / 25

Molarity of liquid HCl if density of solution is 1.17 g/cc, is:

4 / 25

What is the mole fraction of the solute in a 1.00 M aqueous solution?

5 / 25

Number of moles of MnO4 – required to oxidize one mole of ferrous oxalate completely in acidic medium will be:

6 / 25

In Haber’s process, 30 L of dihydrogen and 30 L of dinitrogen were taken for reaction which yielded only 50% of the expected product. What will be the composition of gaseous mixture under the aforesaid condition in the end?

7 / 25

The decomposition of a certain mass of CaCO3 gave 11.2 dm3 of CO2 gas at STP. The mass of KOH required to completely neutralize the gas is:

8 / 25

How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCl?

9 / 25

The number of moles of KMnO4 reduced by one mole of KI in alkaline medium is:

10 / 25

Which has maximum number of molecules?

A). 7 g N2

B). 2 g H2

C). 18 g NO2

D).  16 g O2

11 / 25

The mass of carbon anode consumed (giving only CO2) in the production of 270 kg of aluminium metal from bauxite by the Hall process is (atomic mass of Al = 27):

12 / 25

Concentrated aqueous sulphuric acid is 98% H2SO4 by mass and has a density of 1.80 g mL–1. Volume of acid required to make one litre of 0.1 M H2SO4 solution is:

13 / 25

10 g H2 and 64 g O2 were filled in a steel vessel and exploded. Amount of water produced in this reaction will be?

14 / 25

The number of atoms in 0.1 mole of a triatomic gas is:

A). 1.8 × 1022

B). 6.02 × 1023

C). 1.806 × 1023

D). 3.6 × 1023

15 / 25

An increase in equivalent conductance of a strong electrolyte with dilute dilution is mainly due to:

16 / 25

Find the molar concentration of Na+ ions in a solution of Na2CO3 having 25.3 g Na2CO3 in 250 ml.

17 / 25

Mole fraction of the solution in a 1 molal aqueous solution is:

18 / 25

The Number of water molecules is maximum in:

A). 1.8 g H2O

B). 18 g H2O

C). 18 moles of water

D). 18 molecules of water

19 / 25

What is the mass of participate formed when 50 ml of 16.9% Solution of AgNO3 is mixed with 50 ml of 5.8% NaCl solution? (Ag = 107.8, N = 14, O = 16)

20 / 25

When 22.4 L of H2 is mixed with 11.2 L of Cl2 (g) at STP the moles of HCL formed is equal to:

21 / 25

Suppose the elements X and Y combine to form two compound XY2 and X3Y2. When 0.1 mole of XY2 weights 10 g and 0.05 mole of X3Y2 weight 9 g, the
 atomic weights of X and Y are?

22 / 25

6.02 × 1020 molecules of urea are present in 100 mL of its solution. The concentration of solution is:

23 / 25

If Avogadro number Na is changed from 6.022 × 1023 to 6.022 × 1020 mol this would change:

24 / 25

1 g of Mg is burnt with 0.56 g of oxygen in a closed versel which reactant is left in excess and how much?

A). Mg 0.16 g

B). O2 0.16 g

C). Mg 0.44 g

D). O2 0.28 g

25 / 25

Assuming fully decomposed, the volume of CO2 released at STP on heating 9.85 g of BaCO3 (atomic mass, Ba = 137) will be:

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